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Let the angle between two non zero vectors A(vector) and B(vector ) be 120(degrees) and its resultant be C(vector). Then which of the following is(are) correct?

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The resultant vector is given by R=sqrt(A^2+B^2+2AB cos(theta)), where theta is the angle between vectors A and B R will be minimum when Cos(theta)=-1 that is (theta)=odd integral multiple of Pi Therefore the minimum resultant is R=sqrt(A^2+B^2-2A... Please enable Javascript and refresh the page to continue

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When two vectors are added at an angle different from 90degrees, the resultant vector cannot be calculated using the altered pythagorean theorem formula, it uses its own formula— the Law of Cosines: r 2 = a 2 + b 2 — 2abCosX (where "a," and "b" are the vector magnitues, and x is the angle between the two vectors). This equation only works ...

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If we have V x W = <2, 1, -1> (Cross-Product) and V ⋅ W = 4, (Dot Product) is it possible to find the angle between vectors V and W? Note that I do not actually know values for the vectors, just their products. I was under the impression that I had to know the norms of the vectors to find the angle. Is this not the case? Thanks

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Sep 01, 2015 · The X-component of the resultant vector is the sum of the X-components of each separate vector, and the Y-component of the resultant is the sum of the Y-components of each vector. The angle between the resultant and the X-axis is given by: $$ \theta = arctan(\frac{F_{y}}{F_{x}}) $$ (3) The resultant's magnitude is given by:

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May 03, 2020 · Resolving Vectors. A vector can be ‘broken down’ or . resolved. into its vertical and horizontal components. We can see that this vector can be resolved into two perpendicular components, in this case two to the right and three up.